Calculus/Max/min

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Question
I'm trying to find the point (x,y,z) on the plane 2x-y+z=3 that is closest to the point (2,0,-1).

I used method of elimination of variables, and got the point to be (-5/7 , 18/7, 13/7)

where:
x = -5/7
y = 18/7
z = 13/7

Is this the correct answer?

Answer
No, since 2(-5/7) - 18/7 + 13/7 = -15/7, whereas it should equal 3, which is 21/7.

From what I can see, (2,0,-1) is on the plane defined by 2x - y + z = 3,
for 2(2) - 0 + -1 = 3 - 1 = 3, and that's what the equation says it should be to be on the plain.

Using this, the point that is closest to (2,0,-1) and on the plane is the point itself.

Calculus

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