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Calculus/Derivative of Unit Binormal

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Question
What is the derivative of Unit Binormal in terms of r(t)>

Unit Binormal= r'(t) x r''(t) / ||r'(t) x r''(t) ||

Answer
Hello Roger,

Since the derivative of a cross-product follows the usual "product rule"
and ||r'(t) x r''(t)|| is just a scalar, we get the derivative is:
{[r'(t)]' x r''(t) + r'(t) x [r''(t)]'}/||r'(t) x r''(t)||
= {r''(t) x r''(t) +  r'(t) x r'''(t)}/||r'(t) x r''(t)||, but v x v = 0 (i.e. the zero vector)
= {0 + r'(t) x r'''(t)}/||r'(t) x r''(t)||
= r'(t) x r'''(t)/||r'(t) x r''(t)||

OK?

Abe

Calculus

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Abe Mantell

Expertise

Hello, I am a college professor of mathematics and regularly teach all levels from elementary mathematics through differential equations, and would be happy to assist anyone with such questions!

Experience

Over 15 years teaching at the college level.

Organizations
NCTM, NYSMATYC, AMATYC, MAA, NYSUT, AFT.

Education/Credentials
B.S. in Mathematics from Rensselaer Polytechnic Institute
M.S. (and A.B.D.) in Applied Mathematics from SUNY @ Stony Brook

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