Calculus/Pre-Calculus I
Expert: Paul Klarreich - 2/1/2012
QuestionMr. Klarreich,
I have a question regarding one of your past answers, at
http://en.allexperts.com/q/Calculus-2063/difference-quotient.htm
The original question is:
Evaluate the difference quotient for the given function. Simplify your answer.
F(x)= (1/x)
I'm in the beginning of my first semester of Pre-Calculus. We are going over an introduction to functions. According to my instructor, we are only using differential quotients right now to give us a small taste of Calculus. We haven't actually used differential quotients for anything yet; we are just plugging functions into the formula. My textbook uses this formula for differential quotients:
f(x+h)-f(x)
-----------
h
I fully understand how to get to this point:
x - (x + h)
----------------
x(x + h)
--------------- =
h
The next step, per your previous answer, should bring me here:
- h
------------- =
hx(x + h)
Can you explain what I should be doing to get between these two steps?
Thanks for your time.
AnswerQuestioner:Matt
Country:Nevada, United States
Category:Calculus
Private:No
Subject:Pre-Calculus I
Question:
Mr. Klarreich,
I have a question regarding one of your past answers, at
http://en.allexperts.com/q/Calculus-2063/difference-quotient.htm
The original question is:
Evaluate the difference quotient for the given function. Simplify your answer.
F(x)= (1/x)
I'm in the beginning of my first semester of Pre-Calculus. We are going over an introduction to functions. According to my instructor, we are only using differential quotients right now to give us a small taste of Calculus.
>>>> And how, exactly, does it taste?
We haven't actually used differential quotients
>>>> DIFFERENCE QUOTIENTS, please
for anything yet; we are just plugging functions into the formula. My textbook uses this formula for differential quotients:
f(x+h)-f(x)
-----------
h
>>>>>>>>>>>>>>>
OR:
f(x2) - f(x1) <<< a difference of two things
------------- <<< a quotient of two things.
x2 - x1 <<< a difference of two things
I fully understand how to get to this point:
x - (x + h)
----------------
x(x + h)
--------------- =
h
The next step, per your previous answer, should bring me here:
- h
------------- =
hx(x + h)
Can you explain what I should be doing to get between these two steps?
Thanks for your time.
..........................................................
Start with:
1 1
------ - ---
x + h x
-----------------
h
Clear fractions; multiply each term by the LCD: x(x + h)
x(x + h) 1 x(x + h)1
----------- - ---------
x + h x
----------------------------
h x(x + h)
Cancel a few things:
x....... 1 ..(x + h)1
----------- - ---------
....... ..
----------------------------
h x(x + h)
x - (x + h)
-----------------
h x(x + h)
x - x - h <<<< remove parentheses
-----------------
h x(x + h)
- h <<<< simplify
---------------
h x(x + h)
and you are on your way.