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integrate dx/sinx-sin2x

As written, the problem might be x/sinx - (sin2)x.

When writing sin's, parenthithes are needed, or sin2x is (sin2)x.

I believe it is suppose to be sin(2x).

If the sin(x) and -sin(2x) are integrated, the dx comes after.

I will assume this is asking integral(sin(x) - sin(2x))dx.

The integral of sin(x) is -cos(x) + C and the integral of -sin(2x) is cos(2x)/2 + C.

When put together we get -cos(x) - sin(2x) + C.

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