Calculus/calclus

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Question
integrate dx/sinx-sin2x

Answer
As written, the problem might be x/sinx - (sin2)x.
When writing sin's, parenthithes are needed, or sin2x is (sin2)x.
I believe it is suppose to be sin(2x).

If the sin(x) and -sin(2x) are integrated, the dx comes after.
I will assume this is asking integral(sin(x) - sin(2x))dx.

The integral of sin(x) is -cos(x) + C and the integral of -sin(2x) is cos(2x)/2 + C.
When put together we get -cos(x) - sin(2x) + C.

Calculus

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