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# Calculus/Calculus question

Question

question screenshot(he
given the fact that f'(69)=3 , calculate lim h->0
(f(69+9h)-f(69))/2h

Note that (f(69+h)-f(69))/h is the definition of f'(69), and that is known to be 3.

The only difference h is being multiplied by 9 on the top and 2 on the bottom.

On the top, the measurements are being taken 9 times farther way,
so the answer comes out 9 times as large.

On the bottom, h is multiplied by 2, so the answer turns out to be 1/2 of what it should be.

That makes the answer be f'(69)9/2 = 3*9/2 = 27/2 = 13.5.

Calculus

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#### Scotto

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Any kind of calculus question you want. I also have answered some questions in Physics (mass, momentum, falling bodies), Chemistry (charge, reactions, symbols, molecules), and Biology (reproduction, insusion of chemicals into bloodstream).

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Experience in the area: I have tutored students in all areas of mathematics since 1980. Education/Credentials: BSand MS in Mathematics from Oregon State University, where I completed sophomore course in Physics and Chemistry. I received both degrees with high honors. Awards and Honors: I have passed Actuarial tests 100, 110, and 135.

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