You are here:

- Home
- Teens
- Homework/Study Tips
- Calculus
- Intercepts and Slopes of exponential functions

Advertisement

Hi,

I'm having a little trouble finding finding the intercept and slope of an exponential function. The function is y = 3.53*10^2 e^(2t^2)

My understanding is to get this in linear format the equation would turn into : ln(y)=ln(3.53x10^-2) + 2t^2

I have attached a graph of the function and can see that the curve intercepts y at around 3.52*10^-2 but cannot figure out why the solution to the slope according to the book equals 2.

I would really appreciate some help with this. Thanks in advance

The minimum of an exponential is where the exponent is minimal.

Since the exponent is x^2, the minimum of this is 0.

From this, it can be seen that the graph looks to be correct

and there is no intercept.

The slope is y', and that is y' = 353*e^(2t^2)(4t) = 1412t*e^(2t^2).

This would mean have a quickly increasing or decreasing slope

that quickly went to extremely high values on the right and

extremely small (large negative) on the left.

Calculus

Answers by Expert:

Any kind of calculus question you want. I also have answered some questions in Physics (mass, momentum, falling bodies), Chemistry (charge, reactions, symbols, molecules), and Biology (reproduction, insusion of chemicals into bloodstream).

Experience in the area: I have tutored students in all areas of mathematics since 1980.
Education/Credentials: BSand MS in Mathematics from Oregon State University, where I completed sophomore course in Physics and Chemistry. I received both degrees with high honors.
Awards and Honors: I have passed Actuarial tests 100, 110, and 135.
**Publications**

Maybe not a publication, but I have respond to well oveer 8,500 questions on the PC.
Well over 2,000 of them have been in calculus.
**Education/Credentials**

I aquired well over 40 hours of upper division courses. This was well over the number that were required.
I graduated with honors in both my BS and MS degree from Oregon State University.
I was allowed to jump into a few courses at college a year early.
**Awards and Honors**

I have been nominated as the expert of the month several times.
All of my scores right now are at least a 9.8 average (out of 10).
**Past/Present Clients**

My past clients have been students at OSU, students at the college in South Seattle, referals from a company, friends and aquantenances, people from my church, and people like you from all over the world.