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Could you help me with this problem? I'd really appreciate it.

Thank you for any help!

Make a right triangle with an angle A. Label the far side from the angle as B and the right angle as C. Now label the sides opposite each angle in the same lower case letter. This makes the far side from that angle as a, the near side b, and the hypotenuse as c.

Given this, sin(A) = a/c, cos(A) = b/c, tan(A) = a/b,

ctn(B) = 1/tan(A) = b/a, sec(A) = 1/cos(A) = c/b, and csc(A) = 1/sin(A) = c/a.

If you take aē+bē=cē, it can be transformed by using proper divisions

Note that sinē(x) + cosē(x) = 1, 1 + tanē(x) = secē(x), and 1 + ctnē(x) = cscē(x).

Calculus

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