You are here:

Advertisement

Thank you for taking the time to reply to my question. It is:

Simplify this expression using a sum or difference Identity:

sin(x+y)*sec(x)*sec(y)

If you could please include the steps you used to find your answer as well. Thank you.

Note: sec (x) = 1/cos(x) and sec (y) = 1/cos(y).

Also the formula for sum is sin(x+y) = sin(x) cos(y) + cos(x) sin(y)

So if I were to simplify, I will get:

sin(x+y)*sec(x)*sec(y) = (sin(x) cos(y) + cos(x) sin(y))/(cos(x) * cos(y) )

= (sin(x) cos(y))/(cos(x) * cos(y) ) + (cos(x) sin(y))/(cos(x) * cos(y) )

= sin(x)/cos(x) + sin(y)/cos(y)

= tan(x) + tan(y)

- Add to this Answer
- Ask a Question

Rating(1-10) | Knowledgeability = 10 | Clarity of Response = 10 | Politeness = 10 |

Comment | No Comment |

Calculus

Answers by Expert:

I can answer all calculus question. I am a Math Lecturer and I teach Math in a College, usually Calculus 1, Calculus 2 and Calculus 3 and Linear Algebra.

I have been teaching in this college for more than 12 years. Prior to that, I taught for three years as Visiting Assistant Professor.**Education/Credentials**

I got my doctorate from Univ. of Rochester in Algebraic Toppology. I got a MA from Univ of Rochester, an MA from York Univ. in Toronto and almost did my M.Sc in the National Univ. of Singapore.