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# Calculus/Question

Question
Hello, thank you for taking the time to answer my question. It is solving the multiple-angle equation:
cos(x/2) = -(sqrt3)/2

The basic angle of this equation is given by arcos(sqrt3)/2 = pi/6;

since the cosine function is negative in the 2nd and 3rd quadrant,

we have x/2 = pi- pi/6  or  pi + pi/6

x/2 = 5pi/6,  7pi/6

Hence x= 5pi/3,  7pi/3 (shown)

Depending on the range of values of x (which in this case was not specified), you may have a greater or lesser quantity of answers.

Hope this helps. Peace.

Calculus

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#### Frederick Koh

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I can answer questions concerning calculus, complex numbers, vectors, statistics , algebra and trigonometry for the O level, A level and 1st/2nd year college math/engineering student.

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