Find the linearization function for the function near the given point:

F(x)= sin x + x   near x=pi/3

To find the linear function, we need the slope.
Since the slope is the derivative, note that F'(x) = cos x + 1.
At x = pi/3, F'(x) = 0.5 + 1 = 1.5.

We also need to know f(pi/3) = root(3)/2 + pi/3.

This makes the line into y = root(3)/2 + pi/3 + 1.5(x - pi/3).
That is the same as y = root(3)/2 - 0.5*pi/3 + 1.5x.  


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