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Thank you for your assistance with my question. It is:

Determine the value of c so that the function below is continuous:

f(x)=

x^2-3 x<1

cx+2 x(is equal to or greater than)1

For continuity to happen, you simply need to assert that at the point x=1, both x^2-3 and cx+2 yield the same y value.

Thus, substituting x=1 into both expressions and equating them together gives

1^(2)- 3 = c(1) +2

c=-4 (shown)

Hope this helps. Peace.

Calculus

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