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Find the limit of (x^2-a^2)/x^(4)-a(4) when x->a (x approaches a, I believe). A cannot/doesn't equal 0.

Take b = x^2 and c = a^2.

This is then (b-c)/(b^2 - c^2).

It is known that b^2 - c^2 = (b-c)(b+c).

The (b-c)/(b-c) cancels out, leaving 1/(b+c).

Since b=x^2 and c=a^2, as x approaches a, the b term approaches the c term.

That answer, then, is 1/(2c) = 1/(2a^2).

Calculus

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