Evaluate the limit using L'hopitals Rule

lim x->0 (6^x-11^x)/(x)

L'hospital's Rule states that if 0/0 is gotten,
the top and bottom can be differentiated.

The derivative of the numerator is ln(6)6^x - ln(11)11^x.
The derivative of the denominator is 1.

Putting 0 back in ...
well, any number to the 0 is 1, so all we have is ln(6) - ln(11).
This is the same as ln(6/11).

The value of that is -0.606135804.


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