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Calculus/AP calculus

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Question
Hello. I'm having trouble with this problem.
Find all extrema in the interval [0,2π] if y= x + sin x

Answer
Hello Joyice,

First, y'=1+cos(x)...solving y'=0 gives: cos(x)=-1
Thus, x=pi, for x in [0,2pi], with y''=-sin(x), y''(pi)=0
But, y'(pi-)>0 and y'(pi+)>0
So, at x=pi we have a point of inflection.
Thus, no extrema between 0 and 2pi...the extrema must be
at the end-points: at x=0 and x=pi

OK?

TTYL, Abe

BTW: I've never seen your name (Joyice) before!!!
    Only "Joyce"...what kind of name is "Joyice"?

Calculus

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Abe Mantell

Expertise

Hello, I am a college professor of mathematics and regularly teach all levels from elementary mathematics through differential equations, and would be happy to assist anyone with such questions!

Experience

Over 15 years teaching at the college level.

Organizations
NCTM, NYSMATYC, AMATYC, MAA, NYSUT, AFT.

Education/Credentials
B.S. in Mathematics from Rensselaer Polytechnic Institute
M.S. (and A.B.D.) in Applied Mathematics from SUNY @ Stony Brook

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