AllExperts > Calculus 
Search      
Calculus
Volunteer
Answers to thousands of questions
 Home · More Calculus Questions · Answer Library  · Encyclopedia ·
More Calculus Answers
Question Library

Ask a question about Calculus
Volunteer
Experts of the Month
Expert Login

Awards

About Us
Tell friends
Link to Us
Disclaimer

 
 
 
 
About Abe Mantell
Expertise
Hello, I am a college professor of mathematics and regularly teach all levels from elementary mathematics through differential equations, and would be happy to assist anyone with such questions!

Experience
Over 15 years teaching at the college level.

Organizations
NCTM, NYSMATYC, AMATYC, MAA, NYSUT, AFT.

Education/Credentials
B.S. in Mathematics from Rensselaer Polytechnic Institute
M.S. (and A.B.D.) in Applied Mathematics from SUNY @ Stony Brook


 
   

You are here:  Experts > Teens > Homework/Study Tips > Calculus > Calculus

Calculus - Calculus


Expert: Abe Mantell - 5/29/2007

Question
1- A ladder 25 feet long is leaning against the wall of aa house. The base of the ladder is pulle away from the wall at a rate of 2 feet per second. How fast is the top moving down the wall when the base of the ladder is (a) 7 feet, (b) 15 feet, and (c) 24 feet from the wall?

2- Consider the right formed by the moving ladder, the side of the house, and the ground in Exercise 1. When  the base is 7 feet from the wall, find the rate at which the ares of the triangle is changing

Answer
1. Let x=the distance the base of the ladder is from the bldg, and y=the height.  Thus, x^2 + y^2 = 25^2 = 625
differentiating wrt 't': 2x x' + 2y y'=0 ==> y'=-(x/y) x'
y=sqrt(625-x^2)...y'=-(x/sqrt(625-x^2)) x'
(a) x=7 ==> x'=-(7/24) 2 ft/sec = -7/12 ft/sec
(b) x=15 ==> x'=-(15/20) 2 ft/sec = -3/2 ft/sec
(c) x=24 ==> x'=-(24/7) 2 ft/sec = -48/7 ft/sec

2. Area, A=xy/2...differentiating wrt 't' gives
A'=xy'/2 + x'y/2 when x=7, y=24, x'=2, y'=-7/12
so A'=7(-7/12)/2 + 2(24)/2 = 527/24 sq. ft./sec  

Add to this Answer   Ask a Question


 
User Agreement | Privacy Policy | Kids' Privacy Policy | Help
Copyright  © 2008 About, Inc. AllExperts, AllExperts.com, and About.com are registered trademarks of About, Inc. All rights reserved.