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Calculus/Caluculus (average rates of change)

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Question
I need to calculate the average rate of change for:

R(0)= square root of 4x+1

with intervals given: [0,2]

Answer
To find the average rate of change , evaluate the function at the endpoints of the interval, then find the difference. Then divide by the length of the interval.

R(x) = (4x+1)^1/2

R(0) = ((4)(0) + 1)^1/2 = 1

R(2) = ((4)(2) + 1)^1/2 = 9^1/2 = 3

R(2) - R(0) = 3 - 1 = 2

Average rate of change = 2/(2 - 0) = 2/2 = 1

Calculus

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I can answer questions from the standard four semester Calculus sequence. I am not prepared for questions on Tensor Calculus. Everything else is welcome. Derivatives, partial derivatives, ordinary differential equations, single and multiple integrals, change of variable, vector integration (Green`s Theorem, Stokes, and Gauss) and applications.

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