Calculus/Difference quotient
Expert: Paul Klarreich - 10/2/2006
QuestionFind an algebraic expression for the difference quotient (f(1+deltX)- f(1))/ deltX when f(x)= x^2-(1/x). Simplify the expression as much as possible. Then determine what happens as deltX approaches 0.
AnswerDavid Asks in Category Calculus ...
Subject: Difference quotient
Question: Find an algebraic expression for the difference quotient (f(1+deltX)- f(1))/ deltX when f(x)= x^2-(1/x). Simplify the expression as much as possible. Then determine what happens as deltX approaches 0.
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Hi, David,
You're going to do a lot of this, and it's a bit messy, but essential.
Here's a way to set it up:
WARNING: USE A FIXED FONT, LIKE COURIER, TO VIEW THIS.
Write your function:
1
f(x) = x^2 - ---
x
Write the function expressions used in the DQ:(I'm going to write dx to save typing.)
When you substitute your "1 + dx" or something like it, BE SURE TO PARENTHESIZE CORRECTLY. Nothing is more important than that, and failure to do that leads to most of the difficulties in this computation.
1
f(1 + dx) = (1 + dx)^2 - ------- and simplify a bit:
1 + dx
1
f(1 + dx) = 1 + 2dx + dx^2 - -------
1 + dx
1
f(1) = (1)^2 - --- = 1 - 1 = 0
1
Ok, now. DIFFERENCE QUOTIENT means quotient of differences, so you subtract and then divide.
f(1 + dx) - f(1) =
1
1 + 2dx + dx^2 - ------ - (0) =
1 + dx
1
1 + 2dx + dx^2 - ------
1 + dx
Now divide: Be careful in dividing a fraction. To divide by dx, multiply by 1/dx.
f(1 + dx) - f(1)
---------------- =
dx
1 + 2dx + dx^2 1 1
-------------- - ------ ---
dx 1 + dx dx
Do some algebra, like combining fractions over the LCD of (1 + dx)dx
(1 + 2dx + dx^2)(1 + dx) - 1
----------------------------
(1 + dx)dx
1 + 2dx + dx^2 + dx + 2dx^2 + dx^3 - 1
--------------------------------------
(1 + dx)dx
3dx + 3dx^2 + dx^3
------------------
(1 + dx)dx
Now a factor of dx cancels. THIS IS THE VITAL PART. IF IT DOESN'T CANCEL HERE, YOU SCREWED UP THE ALGEBRA.
3 + 3dx + dx^2
---------------
(1 + dx)
Now that's your difference quotient. The fun part comes next. You let dx -> 0. [Really, all you do is put zero for dx.] Later you will write this as:
lim [THE DIFFERENCE QUOTIENT]
dx->0
3 + 3dx + dx^2
--------------- -->
(1 + dx)
3 + 3(0) + (0)^2
---------------- = 3
(1 + 0)
That's it.