Calculus/Equation of an ellipse.
Expert: Paul Klarreich - 3/22/2007
QuestionPlease can you solve the following :
1) Find the equation of the tangent to the ellipse
( x^2)/9 + y = 1
2) What are the rectangular coordinates of the point (10,
one hundred and fifty degrees ) ?
3) Which of the following ellipses has its center at the
point C ( 2, 1 ) ?
a) x^2 +4y^2 -4x -16y + 4 = 0
0r, ( b), 4x^2 + 9y^2 - 16x -18y - 11 = 0
AnswerQuestioner: Alberto
Category: Calculus
Subject: Calculus
Question: Please can you solve the following :
1) Find the equation of the tangent to the ellipse
( x^2)/9 + y = 1
2) What are the rectangular coordinates of the point (10,
one hundred and fifty degrees ) ?
3) Which of the following ellipses has its center at the
point C ( 2, 1 ) ?
a) x^2 +4y^2 -4x -16y + 4 = 0
0r, ( b), 4x^2 + 9y^2 - 16x -18y - 11 = 0
...................................................
Hi, Alberto,
1) Find the equation of the tangent to the ellipse
( x^2)/9 + y = 1
I think you are missing something. The equation you supplied is for a parabola, not an ellipse. I think you meant:
1) Find the equation of the tangent to the ellipse (x^2)/9 + y^2 = 1, at the point (??,??)
You need that point. So I will just get you started and you can supply the point later and finish.
Use implicit differentiation:
2x/9 + 2y dy/dx = 0
x/9 + y dy/dx = 0
dy/dx = -x/(9y)
Now use the point (??,??) to get the slope and the equation.
2) What are the rectangular coordinates of the point (10,
one hundred and fifty degrees ) ?
Use x = r cos @ and y = r sin @, with:
r = 10, @ = 150 degrees.
3) Which of the following ellipses has its center at the
point C ( 2, 1 ) ?
a) x^2 +4y^2 -4x -16y + 4 = 0
0r, ( b), 4x^2 + 9y^2 - 16x -18y - 11 = 0
To find the center of an ellipse,
A. Complete the square to force the equation into the form:
(x-h)^2 (y-k)^2
------- + ------- = 1
a^2 b^2
B. Then (h,k) are the coordinates of the center.
I'll do this on one of the examples -- the second one.
4x^2 + 9y^2 - 16x - 18y - 11 = 0
4x^2 - 16x + 9y^2 - 18y = 11
4(x^2 - 4x ) + 9(y^2 - 2y ) = 11
4(x^2 - 4x + 4 ) + 9(y^2 - 2y ) = 11 + 16
4(x^2 - 4x + 4 ) + 9(y^2 - 2y + 1 ) = 11 + 16 + 9
4(x - 2)^2 + 9(y - 1)^2 = 36
(x - 2)^2 (y - 1)^2
--------- + ---------- = 1
9 4
Got the idea, now?