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Calculus/Partial Fraction Decomposition

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Expert: - 8/6/2006


Question
I am having trouble with this problem, trying to solve using partial fraction decomposition...

(14x^2 + 6x + 25)/(2x+1)(x^2 + 4)

I cant even set it up right.  Any help would be great.  Thanks,

J

Answer
Set A/(2x+1) + (Bx+C)/(x^2 + 4) =

(14x^2 + 6x + 25)/(2x+1)(x^2 + 4)

so A(x^2 + 4) + (Bx+C)(2x+1) = 14x^2 + 6x + 25

then

A + 2B = 14

B + 2C = 6

A + C = 25

Use your favorite method to solve and get

A = 102/5

B = -16/5

C = 23/5  

Calculus

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