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Calculus/Period of a trigonometric function.

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Expert: - 2/27/2007


Question
The fundamental period of 2cos(3x) is 2pie/3 but why?

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Questioner:   Mayra
Category:  Calculus

Subject:  Fundamental Period
Question:  The fundamental period of 2cos(3x) is 2pi/3 but why?
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Hi, Mayra,

The fundamental period is based on the 'argument' reaching 2pi.  The argument is the quantity to which you apply the function, and in this case it is 3x.

Just set the argument equal to 2pi and solve for x.

3x = 2pi,  gives x = 2pi/3

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