Calculus/Proof of continuity given differntiability at a point.
Expert: Paul Klarreich - 5/8/2006
QuestionHi,
I'm trying to prove that a function f is continuous at a point a given that it is diffentiable at a:
What I've got so far:
a) f is differentiable at a if lim (x->a) (f(x)-f(a))/(x-a) exists at a.
b) f is continuous at a if lim (x->a) f(x) = f(a).
Actually, that's about all I've got! I'm having real trouble linking the two up, even though it looks like it should be a short job...
Any help would be really apprectiated,
Best wishes,
James
AnswerHi, James,
You wrote:
Subject: Proof of continuity given differntiability at a point.
I'm trying to prove that a function f is continuous at a point a given that it is differentiable at a:
What I've got so far:
a) f is differentiable at a if lim (x->a) (f(x)-f(a))/(x-a) exists at a.
b) f is continuous at a if lim (x->a) f(x) = f(a).
Actually, that's about all I've got! I'm having real trouble linking the two up, even though it looks like it should be a short job...
Any help would be really appreciated,
Best wishes,
James
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FIRST: BE SURE TO VIEW THIS IN A FIXED-SIZE FONT.
Try this:
f(x) - f(a)
f(x) - f(a) = ------------ (x - a), if x /= a. [not =]
x - a
Now use some properties of limits, such as:
Lim (AB) = lim A lim B -- Product property.
Lim (A+B) = lim A + lim B -- Sum ...
Lim (A-B) = lim A - lim B -- Difference ...
Lim c = c -- constant ...
Now, where all the limits are as x->a, we write:
f(x) - f(a)
lim (f(x) - f(a)) = lim [----------- (x - a)]
x - a
By the product property:
f(x) - f(a)
lim (f(x) - f(a)) = lim ----------- lim (x - a)
x - a
By the definition of the derivative, and the assumption that f is differentiable at a,
lim (f(x) - f(a)) = f'(a) lim (a - a)
lim (f(x) - f(a)) = f'(a) * 0
lim (f(x) - f(a)) = 0
By the difference property:
lim f(x) - lim f(a) = 0
lim f(x) = lim f(a)
And, finally, by the constant property:
lim f(x) = f(a)