Calculus/I cant find the second derivative please help
Expert: Paul Klarreich - 2/9/2006
Questionx^2+6xy+y^2=8
please show me the work
AnswerHi, nic,
You wrote:
I cant find the second derivative please help
Question: x^2+6xy+y^2=8
please show me your work
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1. there must have been some glitch; I thought I sent this last nite. But no matter.
2. WARNING: THE MATERIAL BELOW MAY CONTAIN FRACTIONS AND OTHER MATERIAL INAPPROPRIATE FOR CERTAIN COMPUTING SYSTEMS. BE SURE TO VIEW IT IN A FIXED-SIZE FONT, SUCH AS COURIER.
Using implicit differentiation:
2x + 6y + 6x y' + 2y y' = 0
x + 3y + 3x y' + y y' = 0
(3x + y) y' = - x - 3y
-x - 3y
y' = -------
3x + y
OK. Now here's the scheme:
1. Use the quotient rule to differentiate that. Since you still have some y-s in it, you will have some y'-s in the result. (Note: I hate using the y' notation, but on the computer I have no choice.)
2. Where you see y', substitute the result we just got.
2.5: Prepare a pot of strong coffee and have an aspirin ready.
3. Simplify.
(3x + y )(-1 - 3y' ) - (-x - 3y)(3 + y')
y'' = ----------------------------------------
(3x + y)^2
(3x + y )(-1 - 3y' ) + (x + 3y)(3 + y')
y'' = ----------------------------------------
(3x + y)^2
(3x + y )(-1) - (3x + y) 3y' + (x + 3y)3 + (x + 3y)y'
y'' = ------------------------------------------------------
(3x + y)^2
-3x - y - 9xy' - 3yy' + 3x + 9y + xy' + 3yy'
y'' = ------------------------------------------------
(3x + y)^2
- y - 9xy' + 9y + xy'
y'' = ------------------------------------------------
(3x + y)^2
8y - 8xy y - x[(-x-3y)/(3x+y)]
y'' = ----------- = 8 ---------------------
(3x + y)^2 (...)^2
Simplify by multiplying each term by (3x+y):
y(3x + y) - x(-x - 3y)
y'' = 8 ----------------------
(...)^3
3xy + y^2 + x^2 + 3xy
y'' = 8 ---------------------
(...)^3
x^2 + 6xy + y^2
y'' = 8 ----------------
(3x + y)^3
Hope I didn't blow too many signs in that.