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your response is incorrect.

pi(r^4) = kt + c

when t = 0, r = 1, therefore c = pi this is true

but

when t = 15, r = 2, c = pi

16pi = 15k + pi

15k = 15pi

k = pi

k does not equal one

just gotta say whoever wrote the first answer and said

15pi = 15k

and then

k = 1

totally throwin me off.

which changes the answer that the second person got (80pi) to just plain 80

the above answer is partially wrong.

15pi = 15k (this is from Above)

k does not equal one

k equals pi

actually, FYI, k=pi because 15(pi) divided by 15 equals pi, and 15k divided by 15 equals k, so k=pi.

I believe there is major mistake made in the solution of this problem.

In the steps solving for k the following was shown:

16 pi = 15k + pi

15 pi = 15k

k = 1

The answer for k should be pi not 1.

For part (a) when you were solving for k, you had:

15 pi=15 k

but you had k=1. k actually equals pi. (k=pi)**

so the answer would end up being (for a):

pi r^4=pi t + pi

r^4=(pi t+pi)/pi

r^4=t+1

r=(t+1)^1/4

I think you may have made a mistake. C/pi = C. Therefore in r^4= (kt +c)/pi simplifies to r^4= (kt/pi) + c. Plug in values of t=0 and r=1, 1= (k(0))/pi + c, c=1.

For part A, everything is correct up until

15 pi = 15k

k = 1

The correct answer is k = pi

Therefore the answer to part A is r = (t + 1)^1/4 after some simplifying

This will also change the answer of part B simply to t = 80

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Calculus

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