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From the last post:

dV 3 pi r^2 dr

-- = -------- -- <--------- 4 IN DENOMINATOR

dt 4 dt

At the instant in question: h = 4, so r = 4h/3 = 16/3. Substituting:

10 = 3 pi (16/3)^2 dr/dt

3 pi 256 dr

10 = -------- -- <--------- 4 NOT IN DENOMINATOR

9 dt

---During the implicit diff, the 4 in the denominator was dropped somehow...

The answer above is incorrect. The author forgot to add the 4 on the bottom when he plugged 16/3 into the equation. In actuality, it should be:

10=(3pi(16/3)^2)*dr

4 dt

10=64pi dr

3 dt

30 =dr

64pi dt

Calculus

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All topics in first-year calculus including infinite series, max-min and related rate problems. Also trigonometry and complex numbers, theory of equations, exponential and logarithmic functions. I can also try (but not guarantee) to answer questions on Analysis -- sequences, limits, continuity.

I taught all mathematics subjects from elementary algebra to differential equations at a two-year college in New York City for 25 years.**Education/Credentials**

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