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Calculus/integral problems with velocity

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Question
let say at t=0, a ball was dropped from a height of 16ft.  it hit the ground and rebounded to a height of 9ft.
a)find a two part formula for the velocity v(t) that is valid until the ball hits the floor a second time
b) at what two times was the ball at height 9ft.

Answer
Hello Danielle,

for the first part (from 16 ft drop to the floor):
v1(t)=-32t, 0<=t<=t1, t1=time until ball hits floor
for the second part (from the floor to 9 ft to floor again)
v2(t)=-32T+Vo, t1<T<t2,
where t2=time until ball hits floor 2nd time, and
Vo=the intial speed of the ball on the bounce, which
can be determined by knowing the height achieved was
9 ft...same as dropping the ball from 9 ft height and
calculating the speed upon impact (just change in sign)...
Once you do that, then you can figure out all times
involved...

OK?

Abe

Calculus

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Abe Mantell

Expertise

Hello, I am a college professor of mathematics and regularly teach all levels from elementary mathematics through differential equations, and would be happy to assist anyone with such questions!

Experience

Over 15 years teaching at the college level.

Organizations
NCTM, NYSMATYC, AMATYC, MAA, NYSUT, AFT.

Education/Credentials
B.S. in Mathematics from Rensselaer Polytechnic Institute
M.S. (and A.B.D.) in Applied Mathematics from SUNY @ Stony Brook

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