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Calculus/rate of change

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Question
Hi,
A point (x,y) is moving along a curve y=f(x). At the instant when the slope of the curve is -1/3, the x-coordinate of the point is increasing at the rate of 5 units per second. The rate of cange, in units per second, of the y-coordinate of the point is -5/3.Why is this true?Please show me how to solve this problem.
Thank you very much.

Answer
Hi, Jeff,

Time is getting short, I know.  Already I was reminded of this when my brother-in-law told us he will be grading AP exam papers again this June.  (Alas, I can't help you -- he is a professor of music, not math.)

Question:  Hi,
A point (x,y) is moving along a curve y=f(x). At the instant when the slope of the curve is -1/3, the x-coordinate of the point is increasing at the rate of 5 units per second. The rate of change, in units per second, of the y-coordinate of the point is -5/3.Why is this true?Please show me how to solve this problem.
Thank you very much.
------------------------------
Here is one form of the chain rule:

dy     dy/dt
--  =  -----
dx     dx/dt

So your second and third sentences say, when translated into the notation of derivatives:

At the instant when dy/dx = -1/3, dx/dt = 5. Then dy/dt = -5/3.

Need I say more?

Calculus

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Paul Klarreich

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All topics in first-year calculus including infinite series, max-min and related rate problems. Also trigonometry and complex numbers, theory of equations, exponential and logarithmic functions. I can also try (but not guarantee) to answer questions on Analysis -- sequences, limits, continuity.

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I taught all mathematics subjects from elementary algebra to differential equations at a two-year college in New York City for 25 years.

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(See above.)

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