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About Philip Carlson Ph.D. (Cand.)
Expertise
Prefer questions regarding general chemistry, analytical chemistry, and physical chemistry. Have less knowledge about organic chemistry but can help with most undergraduate organic chemistry questions not related to reactions and their mechanisms.

Experience
Highly experienced in physical chemistry both theoretical and experimental. Current research focus is fluorescence spectroscopy and electronic structure theory (e.g. quantum mechanics). Past research focus was in analytical chemistry in the area of photocatalysis.

Organizations
American Chemical Society; Society of Christian Philosophers; Evangelical Philosophical Society

Publications
Lori A. Pretzer, Philp J. Carlson, and Joel E. Boyd. "The effect of Pt oxidation state and concentration on the photocatalytic removal of aqueous ammonia with Pt-modified titania." J. Photochem. Photobiol. A: Chemistry. 200 (2008) 246-253. ; Philip J. Carlson, Lori A. Pretzer, and Joel E. Boyd. "Solvent Deposition of titanium dioxide on acrylic for photocatalytic application." Ind. Eng. Chem. Res. 46 (2007) 7970-7976.

Education/Credentials
A.S. in Chemistry from Garden City Community College, Garden City, KS; B.S. in Mathematics from Wayland Baptist University, Plainview, TX; B.S. in Chemistry from Wayland Baptist University, Plainview, TX; Ph.D. (Cand.) in Physical Chemistry at Iowa State University, Ames, IA; B.A. in Evangelism and Missions; M.A. in Theological studies (In progress) from Louisiana Baptist University

 
   

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Chemistry (including Biochemistry) - Chemistry


Expert: Philip Carlson Ph.D. (Cand.) - 11/2/2009

Question
I am trying to help my daughter with this problem, but cannot remember what to do.  I can convert grams to moles but not sure how to do the following problem:  What mass of cobalt contains the same number of atoms as 59.0g fluorine.   thank you for your help

Answer
So in order to answer this question we first need to know how many atoms in 59.0g of F. We can take the molecular weight of F which is 19g/mol. This means for every 1 mole of F I have 19g and for every 19g I have 1 mole. It's just like a dozen eggs. For every dozen I have 12 eggs and for 12eggs I have one dozen. Hence we can take:
59g F (1mol/19g)  grams will cancel and you will get how many mol of F we have. 3.1mol of F in 59g of F.

Now that we know how many moles we have, we need to find how many atoms. We know that for every mole we have 6.022X10^23 atoms. So we can take:
3.1mol F(6.022X10^23)=18.66X10^23 atoms

So what mass of cobalt do we need to have that many atoms. Recognize that for each mol we always have the same number of atoms. That means we need to find the mass (g) that makes up 3.1mol. Since cobalt is 59g/mol and we want 3.1 mol we can take:
3.1mol(59g/mol)  mol will cancel and you will be left with the number of g that makes up 3.1 mol.
3.1mol(59g/mol)=183g.

That means, if we have 183g of Co we will have the same number of atoms as if we had 59g of F.

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