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Cobol/Julian day

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Question
How does one convert the gregorian calander to julian days. I need the code to calculate it. We use Cobol 85. I also need to know how to capture a key and changeits value e.g. contol x or control break.
Thank you
Andre

Answer
IDENTIFICATION DIVISION.
      PROGRAM-ID. MACJUL.
      DATA DIVISION.
      WORKING-STORAGE SECTION.
      01 A.
      05 A1 PIC 9999.
      05 A2 PIC 99.
      05 A3 PIC 99.
      01 B.
      05 B1 PIC 9999.
      05 B2 PIC 999.
      01 C PIC 9 VALUE 2.
      PROCEDURE DIVISION.
      0001.
          DISPLAY "ENTER GREGORIAN DATE(YYYYMMDD):".
          ACCEPT A.
          IF A NOT NUMERIC OR A2 > 12 OR A3 > 31
          DISPLAY "INVALID DATE" GO 0001.
          MOVE A1 TO B1.
          COMPUTE B2 = A3.
          IF A2 = 12 ADD 30 TO B2 SUBTRACT 1 FROM A2.
          IF A2 = 11 ADD 31 TO B2 SUBTRACT 1 FROM A2.
          IF A2 = 10 ADD 30 TO B2 SUBTRACT 1 FROM A2.
          IF A2 =  9 ADD 31 TO B2 SUBTRACT 1 FROM A2.
          IF A2 =  8 ADD 31 TO B2 SUBTRACT 1 FROM A2.
          IF A2 =  7 ADD 30 TO B2 SUBTRACT 1 FROM A2.
          IF A2 =  6 ADD 31 TO B2 SUBTRACT 1 FROM A2.
          IF A2 =  5 ADD 30 TO B2 SUBTRACT 1 FROM A2.
          IF A2 =  4 ADD 31 TO B2 SUBTRACT 1 FROM A2.
          IF A2 =  3 ADD 28 TO B2 SUBTRACT 1 FROM A2
            DIVIDE A1 BY 4 GIVING A1 REMAINDER C
            IF C = 0 ADD 1 TO B2.
          IF A2 = 2 ADD 31 TO B2.
          DISPLAY " ".
          DISPLAY "JULION DATE IS(YYYYDDD):".
          DISPLAY  B1 ":" B2.
          STOP RUN.

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I can answer to any question asked from the domain of cobol including MS COBOL, VS COBOL, VS COBOL I, VS COBOL II, ANSI COBOL-74, ANSI COBOL -85 ans ANSI COBOL -2002. I can also handle JCL, CICS, DB2, IMS, ISPF, IDMS, TSO, MVS, OS/390, VSAM, PL/I and SQL QUESTIONS

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