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About cleggsan
Expertise
All technical areas of Electronics Engineering.

Experience
BSEE, MBA, Design, R&D, University Research.
Senior Life Member of IEEE. Life Fellow of AES.

Organizations
IEEE, Consumer Electronics Society, Audio Engineering Society.
Broad teaching experience; work experience mostly in consumer electronics and conversion from analog to digital technologies. Pioneer in digital audio at all levels.
 
   

You are here:  Experts > Computing/Technology > Job Searching: Technical > Electrical Engineering > computing of load of household usage

Topic: Electrical Engineering



Expert: cleggsan
Date: 7/15/2008
Subject: computing of load of household usage

Question
how to compute how much wattage would consume a 135 watts, electric fan operating in 5 hours.  220 volts 60hertz

Answer
I think you already answered your own question.  The consumption is 135 watts while it is running.

In 5 hours it will consumer 5 X 135 = 675 watt.hours of energy or .675 KWhours.

If you go to this web page:

http://www.mhi-inc.com/Converter/watt_calculator.htm

Move down just a little on that page and enter 675 into the "Watt Hours" blank and press enter; then in the center column enter 5 and set for hours it will calculate all the associated energy values; joules, BTU, Therms, etc.

If you want to know the cost of running the fan for 5 hours just multiply .675 times the KWhour rate that your power company charges.  A typical charge in the USA, for example, is $0.12/KWhour which would then cost the consumer $.12 X .675 = $.08 or 8 cents.

Please let me know if you need more.
C  

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