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Question
Dear Prof Cleggsan

en.wikipedia.org/wiki/Acceleration_due_to_gravity

The value of Acceleration due to gravity is taken as 9.8 m/s square.   How this value is derived and computed and why this number is not any other number viz 6, 8, 12, 15 etc ?.   

Thanks & Regards,
Prashant S Akerkar

Answer
Gravity is the attraction of one body to another. For earth it is related to the size of the earth and the size of the falling object.  Since the earth is very large in comparison with very small, relatively, falling objects that falling rate remains quite steady over the surface of the earth.  If you would travel to other celestial bodies, such as the moon, it would have a different G force due to the smaller mass of the moon compared with earth.

The rate of fall or velocity is easily measured for rough estimates and can also be calculated based on known parameters of the earth.

http://www.dummies.com/how-to/content/how-to-calculate-the-force-of-gravity-on-t

The above walks one through the calculation of earth's G force.

Hope this helps.  

Electrical Engineering

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cleggsan

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All technical areas of Electronics Engineering.

Experience

BSEE, MBA, Design, R&D, University Research.
Senior Life Member of IEEE. Life Fellow of AES.

Organizations
IEEE, Consumer Electronics Society, Audio Engineering Society.
Broad teaching experience; work experience mostly in consumer electronics and conversion from analog to digital technologies. Pioneer in digital audio at all levels.

Education/Credentials
BSEE (Equiv) BYU BSEE University of North Dakota MSBA (MBA) Illinois State University Graduate Studies in Computer Science - Bradley University Graduate Studies - Ohio University Graduate Studies - University of Missouri Kansas City DeVry Tech - Electronics

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