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About John F. Iannuzzi
Expertise
I can answer questions concerning analog and digital circuit design/analysis, switching power supplies, Digital Signal Processing, LASERs, optics and bar code scanning. I can also answer questions about sensors, data acquisition, embedded systems and programming/interfacing to PC based systems.

Experience
I have over 20 years in the electronics industry. I have designed electronic systems for the Aerospace, Nuclear and Material Handling industries. Strong circuit design and analytical skills.

Organizations
IEEE Senior member,(Institute of Electrical and Electronic Engineers)

Education/Credentials
BS Physics, Drexel University

 
   

You are here:  Experts > Computing/Technology > Job Searching: Technical > Electrical Engineering > kirchoffs law

Electrical Engineering - kirchoffs law


Expert: John F. Iannuzzi - 12/1/2005

Question
hi i have a circuit with a 10v battery with a 3 ohm resistor above it then a 10 ohm resistor on its own in a loop in the middle then another resistor which is 2 ohms with a 4v battery below it how do i work out how much curreent is flowing through the 10 ohm resistor? how much voltage is developed across? it and how much power is dissipated in the 10 ohm resistor?


       --------------------------
       |           |             |
       |           |             |
      3 ohm       10 ohm         2 ohm
     resistor      resistor       resistor
       |           |             |
       |           |             |
      10v          |             4v
      supply       |            supply
       |           |             |
       |           |             |
       ___________________________
 
if you could help id be very grateful thanks dave  

Answer
David,
I would solve this problem using super position as follows.  
1.  Zero the 10 volt supply.  This is a short.
2.  Solve the voltage across the 10 ohm resistor with the 4 volt supply.
3.  Zero the 4 volt supply and solve the voltage across the 10 ohm resistor with the 10 (remove the short) volt supply.  
4.  Add the two voltages that you calculated together.  This is the voltage across the 10 ohm resistor.  Now the current and power can be calculated.
Good Luck
John

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