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Electronics/Magnetic effects of electric current.

Question
The force of repulsion between two parallel wires is f when each one of them carries a certain current I.If the current in each is doubled,the force between them would be_______.
Thanking you.

From the Internet, This reference for your consideration:

http://dev.physicslab.org/Document.aspx?doctype=3&filename=Magnetism_CurrentCarr

And from the bottom segment of that page:

"The formula used to calculate these attractive or repulsive forces is:

F =   Bperpendicular IL
F12 =   (µoI1/2πr) I2L2
F12 =   (µo/2πr) I1I2L2
F12 =   (4π x 10-7/2πr) I1I2L2
F12 =   (2 x 10-7/r) I1I2L2

where

F12 represents the force on wire 2 caused by its presence in the magnetic field of wire 1
I1 is the current flowing in wire 1
I2 is the current flowing in wire 2
L2 is the length of the current segment of wire 2 in the field of wire 1
r is the distance between the wires"

The force is linearly related to the distance between the wires and also linearly related to the current flow.

Hope this helps.

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Electronics questions about AC, DC and digital theory.

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Graduate electrical engineer with over 40 years in electronic design, manufacturing, project organization and patent review. Experience in fields of industrial and consumer electronics (audio, video, acoustics, etc.)

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