Electronics/Magnetic effects of electric current.
The force of repulsion between two parallel wires is f when each one of them carries a certain current I.If the current in each is doubled,the force between them would be_______.
Please answer it sir.
From the Internet, This reference for your consideration:
And from the bottom segment of that page:
"The formula used to calculate these attractive or repulsive forces is:
F = Bperpendicular IL
F12 = (µoI1/2πr) I2L2
F12 = (µo/2πr) I1I2L2
F12 = (4π x 10-7/2πr) I1I2L2
F12 = (2 x 10-7/r) I1I2L2
F12 represents the force on wire 2 caused by its presence in the magnetic field of wire 1
I1 is the current flowing in wire 1
I2 is the current flowing in wire 2
L2 is the length of the current segment of wire 2 in the field of wire 1
r is the distance between the wires"
The force is linearly related to the distance between the wires and also linearly related to the current flow.
Hope this helps.