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# Excel/# of minutes greater than in a column

Question
QUESTION: Good day,

Let's say that I have data with timestamps in a an Excel spreadsheet in column A and I want to know how many times the minutes "mm" in hh:mm:ss were greater than "5" minutes as in below timestamps.
Just by looking we know that it is 3 times, but I want to find a formula to find it as in =COUNTIF(A1:A25)...etc.
Excel beginner
Excel 2010 for windows

Thanks!

05:01:49
06:08:52
07:02:16
08:01:40
09:01:23
10:02:17
11:02:00
12:02:14
13:02:57
14:06:21
02:02:39
03:05:02
04:02:46
05:02:39
06:07:32
07:02:15
08:01:59
09:02:12
10:03:25
11:01:48
12:03:42
13:02:15

Here is a user-defined function (UDF) that will count these for you.  In your case you can use it like this:

=NumMin(A1:A22,5)

The first argument is the range containing all the times, and the second argument is the number which the minutes in the time value must exceed to be counted.

Here is the code:
________________________________________________________________

Function NumMin(TimeRng As Range, MaxMinutes As Integer) As Long
'returns the number of time values in range TimeRng whose minutes
'part exceeds MaxMinutes
Dim Cell    As Range 'a cell in TimeRng
NumMin = 0
For Each Cell In TimeRng
If Minute(Cell) > MaxMinutes Then NumMin = NumMin + 1
Next Cell
End Function
_________________________________________________________________

You can simply paste this code into a standard macro module and this UDF will be immediately available.

Damon

---------- FOLLOW-UP ----------

QUESTION: Hi Damon,

What about if I wanted to find how many times the minutes and seconds "mm:ss" were greater than "6:59" 6 minutes and 59 seconds with the timestamps above?

Thanks,

Here is a modified UDF that you can use to do what you describe:
________________________________________________

Function NumMinSec(TimeRng As Range, MaxTime As Date) As Long
'returns the number of time values in range TimeRng whose minutes
'part exceeds MaxMinutes (actually a string representation of a
'time value, such as "06:59"
Dim Cell    As Range 'a cell in TimeRng
NumMinSec = 0
For Each Cell In TimeRng
If StripHours(Cell.Value) > CDate(MaxTime) Then NumMinSec = NumMinSec + 1
Next Cell
End Function

Function StripHours(T As Date) As Date
'strips hours off of time value, leaving only minutes and seconds.
'example, 14:06:21 yields a time value of 06:21
StripHours = T - Hour(T) / 24
End Function
_______________________________________________

Note that you must include the StripHours helper function.

When you use this function you must specify the hours and minutes of the max hour and minute value including a leading zero for the hour value as a text string like this:

=NumMinSec(A1:A22,"0:06:59")

Damon

---------- FOLLOW-UP ----------

QUESTION: Great Damon, it works well! Much appreciated! Now my last question (hopefully):)

What about if I want to compare two columns and find the # of times the time in column B is greater than column A by 5 minutes.

d/h:m   h:m:s
10307   3:08:44
10320   3:22:08
10348   3:56:43
10635   6:36:28
10650   6:55:02
10719   7:20:59
10730   7:36:36
10845   8:46:21
11032   10:33:58
11241   12:43:32
11620   16:22:01
11715   17:20:10
11734   17:36:40
11745   17:46:19
11835   18:36:46
30209   2:10:11
40341   3:42:35
40550   5:51:47
41623   16:23:55
41721   17:22:12
41824   18:25:16
41947   19:49:02
42021   20:26:59
50150   1:51:19
62113   21:14:35
70145   1:46:44
70210   2:11:59
70317   3:24:02
70546   5:47:44
70634   6:36:07
70827   8:28:53
70854   8:57:22
71125   11:26:13
71740   17:41:43
72057   20:58:33
81145   11:46:43
81241   12:42:11
81406   14:07:13
81513   15:13:39
81715   17:15:50

Thank you!

Pablo

Hi again Pablo,

Here's some code:

________________________________________________________

Function NumDif(TimeRng As Range, MaxDif As Single) As Long
'returns the number of time values in the second column of range TimeRng
'exceeds the values in the first column of TimeRng by more than MaxDif,
'a decimal number of minutes.
Dim Cell     As Range 'a cell in TimeRng
Dim MaxDifD  As Date  'MaxDif value in days
MaxDifD = MaxDif / 1440#
NumDif = 0
For Each Cell In TimeRng.Columns(2).Cells
If Cell - Cvt2Date(Cell.Offset(0, -1).Text) > MaxDifD Then NumDif = NumDif + 1
Next Cell
End Function

Function Cvt2Date(DHM As String) As Date
'converts 5-6 digit numbers to h:m assuming numbers are in the form
'ddhhmm (e.g., 41947 is equivalent to 19h 47m)
Dim MM      As Integer
Dim HH      As Integer
MM = CInt(Right(DHM, 2))
HH = CInt(Left(Right(DHM, 4), 2))
Cvt2Date = TimeSerial(HH, MM, 0)
End Function
_______________________________________________________

In this case you would call the UDF like this:

=NumDif(A2:B41,5.0)

Note that the decimal part of the minutes (5.0) does matter, so for example 5.1 would indicate a time difference of 5 minutes 6 seconds.

Damon
Questioner's Rating
 Rating(1-10) Knowledgeability = 10 Clarity of Response = 10 Politeness = 10 Comment Hi Damon, Thank you very much! Maybe I am doing something wrong but the last one doesn't seem to compute the value...can you check please? Pablo

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#### Damon Ostrander

##### Expertise

I have extensive experience with VBA programming in Excel 5 through Excel 2013. As a former aerospace engineer with a large aerospace corporation and consultant in a small defense technology services company, I have developed a wide range of applications in VBA, including simulations involving mixed-language programming, satellite orbit mechanics, graphics and animation, and real-time applications. I am interested in moderate to hard VBA-related questions only.

##### Experience

I have developed and taught several courses in Excel VBA programming and also VBA programming in Office 97, 2000, and 2007. I have developed a number of large technical applications in Excel VBA for use within the aerospace industry.

Education/Credentials
B.S. in Electrical Engineering and Computer Science, University of California, Berkeley.