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About Thomas J. Baglin
Expertise
Have been an Expert on www1.askme.com for about 2 years in Geography, Maps, and Other Geography. Recently have applied and received same status in Military History, and International Politics. Please no direct homework questions.

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See above.

 
   

You are here:  Experts > Science > Geography > Geography > Volume of Mount Everest

Geography - Volume of Mount Everest


Expert: Thomas J. Baglin - 6/29/2005

Question
Hi Thomas,

That diagram you found is great. Using the formula for a volume of a cone
1/3*pi*radius squared*height with pi=3.1416, radius=16km = 10 miles* 1.6 km/mile, height=9km. I calculate that the

volume of Mt Everest is approximately 2413 cubic kilometers.

Thanks for finding that diagram!

-------------------------
Followup To
Question -
Hi,

I would like to know an estimate of the volume of Mount Everest is in cubic meters. I know how high it is, but I haven't been able to find any estimates of its volume.

Thank for your help.
Answer -
Larry:

    I am a CLUTZ in Math!  Simple COMPUTATION by the basics, I am pretty good at.  Anything beyond "2+2," and you need a "Rocket Scientist."  BTAIM, I do believe I can get you an APPROXIMATE figure.  I STRESS APPROXIMATE ----AGAIN!  After my fumbling attempt, I suggest you check with some of the Math whizzezs at the "Math" portion of www.allexperts.com.  They might be able to refine what I present.  Let us proceed.

    After a "Google" search, I found this site, with a marvelous depiction:  http://www.the-aps.org/publications/tphys/legacy/1982/issue1/36.pdf.  Scroll down to page 2.

    Using the values of 9km as the height, and the diagram shows a 32.18688 distance to the CENTER of the mountain, we can double that to get the full base of 64.37376km.  we then DOUBLE that as the LENGTH of the base would be APPROXIMATELY the same for the WIDTH, and leaves us with 4,143.9603 SQ.km., as an AREA at the BASE of the occupying mountain.

    To use the 9km HEIGHT, we then come up with 37,295.642_ _ _ _ CUBIC KILOMETERS.

    I do NOT LIKE the metric system, as I was brought up under the IMPERIAL system, which has stood the test of time quite well, I am far more comfortable with that system.    I make this comment as in the Metric System, you just move the "dot," around to get your proper rank in ITS system.  In my case, I used this site for speedy conversions: http://www.onlineconversion.com/length_common.htm.  HOWEVER, it does NOT go into square, and cubic categories.

    Granted, I AM workig with ROUNDED/"Perfect" measurements to achieve the result.  But it SHOULD be correct in terms of the PROCESS.

    Please access the Math portion of www.allexperts.com to make any corrections needed.

    Concurrently, I will seek another source to provide more accurate info.  But, this SHOULD give you an idea of the dimensions of Mt. Everest.

Thomas J. Baglin
Ragingmt@rochester.rr.com
06-28-05

Answer
Larry:

    I am pleased you have found the correct culmination of the configuration. However, I wish to point out some matters that raised some questions --- FOR ME.

    Why the use of the formula for a cone?  Would not Everest be more correctly a PYRAMID?  On a 2-dimension picture, a cone, triangle would be correct in usage?  But, we are doing a three-dimensional computation, eh?  Everest does have FOUR sides?

    In the diagram, the 10 mile designation is only the RADIUS.  The BASE , both East-West, North-South; would be DIAMETERS --- oui?  Hence the total base length on each axis would be 20 miles = 32.18688km.  Squareing that, we have 1035.9952sqkm., as the area. 9,323.9568ckm is what I SHOULD have arrived at as the volume of the CUBE.  

    In my fumbling around, I made the mistake of using the wrong measurement in the area measurement, hence the wrong volume.

    I also "completed the square" in terms of the cube.  The 9km figure is just the high point of the mountain.  Thus, IF you were to put a box over the mountain that is how big it would have to be to cover it top to bottom, corner to corner.  As for exactness, I would say that YOUR computations are superior to mine, in this regard.

    Now you KNOW WHY I never went into ACCOUNTING or Rocketry!!

Thomas J. Baglin
Ragingmt@rochester.rr.com
06-29-05




Larry:

    This is a response sent to me from the Rochester Public Library --- http://mcls.rochester.lib.ny.us/.  Great resource; use "Ask The Librarian" link, and follw the instructions.

"From: Science Reference 1
Date: 06/29/05 12:30:17
To: Ragingmt@rochester.rr.com
Subject: RE: Online Ref.

 

-----Original Message-----
From: RIC Info Desk 1
Sent: Wednesday, June 29, 2005 10:42 AM
To: Science Reference 1
Subject: FW: Online Ref.


No math whiz's here either but the hardest part of your question is where to determine the actual base of the mountain.  Since Everest is a chain of mountains there are many foothills so one has to deside where they want to begin measuring. Using your figures the easiest way to determine the size is to use the formula for finding the area of a cone which is basically what a mountain is,

Volume of a Cone V= 1/3 x p x radius2 x height (p= 3.14)


 V= 1/3 x p x radius2 x height
V= 1/3 x 3.14 x (3)2 x 12

V= 1/3 x 3.14 x 9 x 12

V = 1/3 x 3.14 x 108

V = 1/3 x 339.12

V = 339.12/3

V = 113.04 cm3

You can also check at the following web site for more formulas that might also help give you the dimentions.  http://cite.telecampus.com/GED/math.html#sqpyr

Hope this helps some.

Thank you"

    They too, used the cone as its computational source configuration.

    This is all Greek to me, though.

Thomas J. Baglin
Ragingmt@rochester.rr.com
06-29-05

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