AboutAzeem Hussain Expertise I can answer virtually any kind of question dealing with of Math 536 and below, my forte being in parabolic functions and analytical geometry.
I'm currently learning Linear Algebra, and cannot answer questions that deal with subject matter more advanced than that.
Experience I am neither a professor nor a teacher of this subject. I am merely a student who is gifted at mathematics and enjoys being of service to his community. I frequently tutor people in math and the results are usually great.
Publications Reflections, Riverside School Board (2005, 2006)
Education/Credentials Diploma of Secondary Studies from Chambly Academy High School, and IBO-MYP certificate as well. My lowest mark on a high school math final was 97%, peaking at 99% in 2006 and 2007 (second-highest Math 436 mark in the province). Being a Quebecer, I am fluent in English and French and can respond to questions easily in both languages.
Awards and Honors Pascal Math Competition, School Champion(2007)
Question I don't understand how to find the lateral area for regular prism. Can you explain in steps how do i find the lateral area?
Answer Hi Joe!
A regular prism has 6 faces, all of which are rectangles. I'll ask you to draw a rectangular prism(ideally one where all the 3 dimensions look different). Label the dimensions l, w, and h for length, width, and height. Ensure every edge is labelled. Now look at each rectangular face independently of every other. You know the area of a rectangle is the product of its two dimensions, which are clearly labelled in your diagram right now. Find the areas of the all the rectangles and add them together. You should end up with:
A=lw+lw+wh+wh+lh+lh
A=2(lw+lh+lw)
Another way of thinking about it would be this. Look at the prism as having 2 bases and a long "mural" bridging the two. This mural is a long rectangle, whose height is that of the prism and whose length is the base perimeter of the rectangle. That makes (2l+2w)h. You must know account for the bases, which are the product of the non-height dimensions. You have 2 of them, so 2lw. Adding all this together:
A=(2l+2w)h+2lw
A=2(lh+wh)+2lw
A=2(lh+wh+lw)
