AboutAzeem Hussain Expertise I can answer virtually any kind of question dealing with of Math 536 and below, my forte being in parabolic functions and analytical geometry.
I'm currently learning Linear Algebra, and cannot answer questions that deal with subject matter more advanced than that.
Experience I am neither a professor nor a teacher of this subject. I am merely a student who is gifted at mathematics and enjoys being of service to his community. I frequently tutor people in math and the results are usually great.
Publications Reflections, Riverside School Board (2005, 2006)
Education/Credentials Diploma of Secondary Studies from Chambly Academy High School, and IBO-MYP certificate as well. My lowest mark on a high school math final was 97%, peaking at 99% in 2006 and 2007 (second-highest Math 436 mark in the province). Being a Quebecer, I am fluent in English and French and can respond to questions easily in both languages.
Awards and Honors Pascal Math Competition, School Champion(2007)
Question From a point A, the angle of elevation of the top of a transmission tower is 57*. At the point B, 45m closer to the tower, the angle of elevation of the top is 72*. How high is the tower?
Answer Hi Irene,
Begin by sketching the situation. Assume the tower is perpendicular to the ground. You will have a big right triangle with angle of elevation of 57º, height h and base (45+x). Inside that triangle, you'll have a second right triangle with angle of elevation 72º, height h, and base x. You'll need a system of equations to solve for h. Begin by looking at the small triangle.
tan72º=h/x
x=h/tan72º
Now look at the big triangle. Set up a similar equation.
tan57º=h/(45+x)
(45+x)tan57º=h
45tan57º+xtan57º=h
Recall that x=h/tan72º. Substitute.
45tan57º+htan57º/tan72º=h
45tan57º=h-htan57º/tan72º
Factor our h.
45tan57º=h(1-tan57º/tan72º)
h=[...]
h=138.68
