AboutAzeem Hussain Expertise I can answer virtually any kind of question dealing with of Math 536 and below, my forte being in parabolic functions and analytical geometry.
I'm currently learning Linear Algebra, and cannot answer questions that deal with subject matter more advanced than that.
Experience I am neither a professor nor a teacher of this subject. I am merely a student who is gifted at mathematics and enjoys being of service to his community. I frequently tutor people in math and the results are usually great.
Publications Reflections, Riverside School Board (2005, 2006)
Education/Credentials Diploma of Secondary Studies from Chambly Academy High School, and IBO-MYP certificate as well. My lowest mark on a high school math final was 97%, peaking at 99% in 2006 and 2007 (second-highest Math 436 mark in the province). Being a Quebecer, I am fluent in English and French and can respond to questions easily in both languages.
Awards and Honors Pascal Math Competition, School Champion(2007)
I've been trying to solve them for a few hours and can't seem to find any way to solve them. If you could just explain an easy way to solve them I'll find the answer, I just can't set them up.
Answer Hi Anthony!
For question 4, you know the total perimeter is equal to twice the side of the square plus twice the length of the small arcs. Find the side of the square in terms of r by the Pythagorean Theorem. Knowing the central angle, you can find the angle measure of the arc and then turn that into a fraction of the whole circumference (2πr/4). Knowing the perimeter, you can solve for r.
For question 5, use a similar approach to get started. Using the given angle information, find the angle of the arc that is missing from the circle. You know the perimeter of the figure is the circle's circumference minus the arc plus the two edges that form the angle.
For question 6, subdivide the figure into a semicircle and a right triangle. One side of the triangle is 7, the other is 2r. Find the measure of the third side in terms of r. You know the figure's perimeter is equal the the circle's semiperimeter (2πr/2) plus the length of the side you just solved for. You can solve for r by forming a quadratic equation.
Sorry if this is a bit wordy or unclear. I was trying to do this without setting up the algebraic equations. Ask a follow-up if you're still confused.
