Question How would I find the chord length of a segment if the radius of the curvature is 10 ft. and the height of the segment is 2 ft.?
Answer I forgot to send the picture with my response.
I wish that could be attached at first, but I have to wait until I have previewed it at first.
This is not to you, but to the people who run it, and I think they read the answers.
They should have a box to ask what to attach when the answer is sent before the answer is previewed. Or maybe they should have a place to attach a picture to the updates.
Anyway, the rest is to you.
The drawing had a picture with a circle that had radius 10.
There are 2 feet above the ground on the radius of the circle going straight up.
This means there is a right triangle below the groun of height 8 ft and hypoteneuse 10.
Now 10² - 8² = 100 - 64 = 36 = 6².
This means that there are two triangles below the ground, each with area 8•6/2.
When added together, they have are 8•6=48.
The angle at the center of the circle α is known to satisfy cos(α) = 10/8.
There is another angle that is equal as the triangle is reflected.
This means the inside angle is 2•cos(α).
Combined with my last response, if this doesn't do it, write back and I'll send you the picture.
