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About Azeem Hussain
Expertise
I can answer virtually any kind of question dealing with of Math 536 and below, my forte being in parabolic functions and analytical geometry. I'm currently learning Linear Algebra, and cannot answer questions that deal with subject matter more advanced than that.

Experience
I am neither a professor nor a teacher of this subject. I am merely a student who is gifted at mathematics and enjoys being of service to his community. I frequently tutor people in math and the results are usually great.

Publications
Reflections, Riverside School Board (2005, 2006)

Education/Credentials
Diploma of Secondary Studies from Chambly Academy High School, and IBO-MYP certificate as well. My lowest mark on a high school math final was 97%, peaking at 99% in 2006 and 2007 (second-highest Math 436 mark in the province). Being a Quebecer, I am fluent in English and French and can respond to questions easily in both languages.

Awards and Honors
Pascal Math Competition, School Champion(2007)

 
   

You are here:  Experts > Science > Math for Kids > Geometry > Complementary Angles

Geometry - Complementary Angles


Expert: Azeem Hussain - 9/18/2009

Question
Hello Azeem,

My daughter posed this question to me, and I can't seem to solve it: Angle A and Angle B are complementary.  Angle A has a value of -2x2 (negative 2x squared) + 10; Angle B has a value of 8x + 16.  What is the value of x and what are the associated angles?

I tried the standard solution -2x2 + 10 + 8x + 16 = 90 and resolved it to -2x2 + 8x = 64; then further to x2 - 4x + 32 = 0, but from there I’m stuck, since the +32 value cannot be factored to result in a negative 4 in the - 4x term.

Can you help? Could the -2x2 be a typo and if it is, how to solve for a value of 2x2?  I'm stumped!

Thanks and regards,
Mike Majlak

Answer
Hi Mike!

As written, there is no solution to the quadratic equation.

Assuming there is a typo and it's supposed to be positive 2x², the equation becomes
2x²+8x-64=0
x²+4x-32=0

Which can be factored as
(x+8)(x-4)=0

Therefore x=-8, and x=4.

<B=8x+16
<B=8(-8)+16
<B=-48

Uh oh!  Both angles must measure between 0 and 90 degrees, so -48 degrees is nonsensical.  Therefore, x may not equal -8 in this problem.  It must equal 4.  Substituting x into the initial expressions for the angles measures, <A=42° and <B=48°.

Thanks for asking,
Azeem

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