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Geometry/area of equilateral triangle given only radius

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bhause wrote at 2007-06-03 02:22:38
I believe step 3 was calculated wrong.



(1/2) * base * height should be

(1/2) * 3(sqrt(3))/2 * height

(1/2) * 3(sqrt(3))/2 * 3

(1/2) * (9/2)sqrt(3) <---

not

(3/4)*sqrt(3)



Ultimately the formula for finding the area is

A = (3/4)sqrt(3)(r^2)


Joe wrote at 2013-02-23 21:01:38
(sqrt(3)/2) * 6 i.e. 3*sqrt(3)       ...(2)

The area of the triangle OBD

= (1/2) * base * height

= (1/2) * sqrt(3)/2* 3

= (3/4)*sqrt(3)          ...(3)



I think this is wrong....

The base was calculated to be 6*sqrt(3)/2 so the equation for the area of the triangle should be

=(1/2) * (6*sqrt(3)/2) * 3. Or = (1/2) * (3*sqrt(3))*3


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