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I believe step 3 was calculated wrong.

(1/2) * base * height should be

(1/2) * 3(sqrt(3))/2 * height

(1/2) * 3(sqrt(3))/2 * 3

(1/2) * (9/2)sqrt(3) <---

not

(3/4)*sqrt(3)

Ultimately the formula for finding the area is

A = (3/4)sqrt(3)(r^2)

(sqrt(3)/2) * 6 i.e. 3*sqrt(3) ...(2)

The area of the triangle OBD

= (1/2) * base * height

= (1/2) * sqrt(3)/2* 3

= (3/4)*sqrt(3) ...(3)

I think this is wrong....

The base was calculated to be 6*sqrt(3)/2 so the equation for the area of the triangle should be

=(1/2) * (6*sqrt(3)/2) * 3. Or = (1/2) * (3*sqrt(3))*3

I will try to solve Geometry related problems of High-School and Junior college level.

Experience in part-time teaching.**Education/Credentials**

Post Graduate in Applied Maths. .