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Question
I was given this question:"A number is said to be a step number if for each pair of consecutive digits in the no. the difference is 1 (eg:456567). Single digit numbers can be considered as step numbers."

Here's the code I've written:

import java.util.*;
public class question2 {
  public static void main(String[] args){
     Scanner s = new Scanner(System.in);
     System.out.print("Input Nmber:");
     int x = s.nextInt();
     String y = s.nextLine();
     int a = y.length();
     int r1 = 0;
     int r2 = 0;
     int z = 0;
     int c = 0;
     int i = 0;
     while(i>a){
        r1 = x%10;
        r2 = ((x%100)-r1)/10;
        c = r1-r2;
        if (c != 1){
         z = 1;
        }
        x = x/10;
        i = i+1;
     }
     if(z==0){
        System.out.print("step");
     }
     else{
        System.out.print("not step");
     }
  
     
  }

}
the problem is that the code ALWAYS gives me "step" even if the no. is not!! and I don't know why is that!!!
I really need a very quick reply! Thank You in advance.

Answer
Hello,

Sorry, I am abit late on this. Been busy with other things.

suppose, the user enters a number(456567) now, you do know for it to be a step number, you have to be sure that 4-5==5-6==6-5==5-6==6-7 ={1} absolute value of 1 right?

If that is what your programme should do, then
1. get the number
2. run a for loop on each digit in the number set
3. find the difference between the present digit and the digit next
4. if the difference is either 1 or -1
5. Then it is a step number
6. else
      i.e if during the loop you find a single difference that is not 1 or -1 the whole set has been contaminated by that single
     difference, you have to conclusively conclude it is not a step number..

Now, apply this concept to your code and am sure it will work fine :) sorry for the late reply.

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