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Metallurgy/Chemical analysis


"I did an experiment with cooper wire which is as follows:

First I took a copper wire and burnt it in excess of oxygen in a bunsen flame.

Black copper(II) oxide was formed.

Now I want to know how I could proceed with to obtain a final result of copper(II) chloride using sodium chloride.

Just for the sake of information I study in tenth grade.

An eager student,

Dear AB.

I had already answered this question.It seems you want to know the way of experiment which is as under:
Electrolysis (of copper chloride) is a way of splitting up (decomposition) of the compound (copper chloride) using electrical energy. The electrical energy comes from a d.c. (direct current) battery or power pack supply. A conducting liquid, containing ions, called the electrolyte (aqueous or molten sodium chloride), must contain the compound (copper chloride) that is being broken down. The electricity must flow through electrodes dipped into the electrolyte to complete the electrical circuit with the battery. Electrolysis can only happen when the circuit is complete, and an electrical current (electricity) is flowing, then the products of electrolysing aqueous copper(II) chloride solution are released on the electrode surfaces where they can be collected. Electrolysis always involves a flow of electrons in the external wires and electrodes and a flow of ions in the electrolyte and there is always a reduction at the negative cathode electrode (which attracts positive ions, cations) and an oxidation at the positive anode electrode (which attracts negative ions, anions) and it is the ions which are discharged to give the products.

Hope it meets your requirement,

Happy Christmas,


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