AllExperts > Number Theory 
Search      
Number Theory
Volunteer
Answers to thousands of questions
 Home · More Number Theory Questions · Answer Library  · Encyclopedia ·
More Number Theory Answers
Question Library

Ask a question about Number Theory
Volunteer
Experts of the Month
Expert Login

Awards

About Us
Tell friends
Link to Us
Disclaimer

 
 
 
 
About Vijilant
Expertise
Most questions on number theory, divisibility, primes, Euclidean algorithm, Fermat`s theorem, Wilson`s theorem, factorisation, euclidean algorithm, diophantine equations, Chinese remainder theorem, group theory, congruences, continued fractions.

Experience
Teacher of math for 50 years

Organizations
ATL

Publications
Journal of mathematics and its applications

Education/Credentials
BSc Hons Liverpool

Awards and Honors
State Scholarship 1955

Past/Present Clients
I taught John Birt, former Director of the BBC in 1961. His homework book was the most perfect I have ever marked. And also the most neat. I could tell he was destined for great things. One of my classmates was the poet Roger McGough, and I have a mention in his autobiography.

 
   

You are here:  Experts > Science > Mathematics > Number Theory > Number Theory

Number Theory - Number Theory


Expert: Vijilant - 10/26/2009

Question
if n>4 is a composite number, show that n|(n-1)! Conclude that (n-1)! is not congruent to -1(mod n).

Answer
Hello Surya
Unless n is a square, it can be factorised, and both of these factors are less than n, and can be found as factors of (n-1)!.  
So what happens when n is a square.  n = 4 is an exception.  But for any other square,
k^2, both k and 2k are factors of (k^2-1)!

Best wishes

vijilant

Add to this Answer   Ask a Question


 
User Agreement | Privacy Policy | Kids' Privacy Policy | Help
Copyright  © 2008 About, Inc. AllExperts, AllExperts.com, and About.com are registered trademarks of About, Inc. All rights reserved.