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Hi, I'm really stuck on this question that I have to do for an assignment.. I've tried to google a formula but I can't find any that seem to fit.. here is the question:

"In the Bohr Model of the hydrogen atom an electron of mass 9.1X10^-31kg is considered to e moving in a circular orbit of Radius 5.3X10^3km s^-1 around a central proton. Calculate the acceleration of the electron."

Please help me if you can and explain!

Thank you very much, Aoife!

For an electron moving in a circular path around the nucleus you will need to use Newton's 2nd Law: SF=m*a

For this orbiting electron the only relevant force will be the electrostatic force and the acceleration is centripetal. Therefore:

SF=Fe=k*q^2/R=m*ac where k=9*10^9N*m^2/C^2, R is the Bohr Radius R=5.3*10^(-11)m, q is the elementary charge q=1.6*10^(-19)C and m is the mass of the electron m=9.11*10^(-31)kg.

Solving for the centripetal acceleration this becomes:

ac=k*q^2/(m*R)=9.0*10^9*(1.6*10^(-19))^2/(9.11*10^(-31)*5.3*10^(-11))=9.0*10^22m/s^2

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I am teaching or have taught AP physics B and C [calculus based mechanics & electricity and magnetism] as well as Lab Physics for college bound students. I have a BS in Physics from the University of Pittsburgh and a Master of Arts in Teaching from same. I have been teaching physics for 34 years. I am constantly updating my skills and have a particular interest in modern physics topics.