I am currently a junior in high school taking honors physics and am having some serious trouble solving the below problem. Thanks in advance!
A 2.44 kg block is pushed 1.55 m up a vertical wall with constant speed by a constant force of magnitude F applied at an angle of 69.6 degrees with the horizontal. The acceleration of gravity is 9.8 m/s2 .
If the coefficient of kinetic friction between the block and wall is 0.691, find the work done by F .
Answer in units of Joules
Resolve the force, F, into two components, Fv (vertical) = Fsin(69.6) and Fh (horizontal) =
Fcos(69.6). The frictional force = 0.681Fh. The vertical force has to overcome mg which equals 2.44(9.8) and the frictional force. So Fsin(69.6) = 23.91+0.681Fcos(69.6).
Solve for F and then the work = F(1.55)