Hi, I was just wondering if I could get some help with the number 1? How do you explain that the circuit from the diagram follows the loop rule?
Is it because the red and blue add up to 0?
I have to guess what the circuit looked like. Resistor in series with a resistor connected across a voltage source is my guess. The text refers to a generator and then says "battery connected" and later says "no battery". I'm going to guess that the "generator" is a signal generator with output of 0V,6V,0V,6V, .... And the timing must be controlled so the duty cycle is 50/50. I assume the red trace was voltage across the cap and the blue trace was the voltage across the resistor.
My answer will be no better than the accuracy of my guess at what your setup was. At any time, the voltages indicated by the red and blue traces should add up to whatever the output of the generator is. So it should add up to 6V half of the time and should add up to 0V half of the time. That's not what I see on your plot. If the generator is putting out 6V, the sum of the voltage drops across the 2 components should be 6V -- any time that 6V is the input to the circuit. That would be according to Kirchhoff.
It looks to me like you did not have your scope synching correctly (trigger off the generator signal). The relative timing of the 2 traces seem to be skewed from what I would expect. The voltage across the resistor would be proportional to the current through it. Therefore it should be maximum, 6V, when the voltage across the cap is just starting to climb from 0V. Once the cap is fully charged to 6V, the current through the resistor would be zero so the voltage across it should be zero.
I hope this helps,