Physics/special relativity speed of light
Let's consider two cars A & B
Both cars are at rest in position O. Now both
cars started moving in opposite direction with
same velocity 2m/s for A & B in opposite direction
So the speed of car B relative A is = 2+2= 4m/s, right?
Now let's consider two photons X & Y moving in opposite
direction, from a starting point O. each photon have its own velocity, that is ící so what is the speed of íPhoton Bí relative To
i know the speed of photon from the starting point is ící
but just like in the case of cars the relative speed of Photon B from Photon A should be added, isn't it? therefore it becomes 2*c??
if not why! why is it said that the spotted of light is constant from every frame of reference?
(btw please don't include a 3rd observer here)
This is a perplexing fact about speeds close to the speed of light. Actually, the following formula applies to both of your cases:
w = (u + v) / (1 + u*v/c^2)
where w is the relative speed between the 2 bodies. The speed of A is u and the speed of B is v.
Let's use the formula with the 2 cars:
w = (2 m/s + 2 m/s) / (1 + (2 m/s)^2/(3x10^8 m/s)) = (4 m/s) / (1 + 4/9x10^16)
The value of c^2 is so large, that the term 4/9x10^16 is essentially zero. Therefore the result of the formula is that w = 4 m/s.
It's only when u and/or v is close in value to c that the result of the formula is surprising. Using the formula on your 2nd case:
w = (c + c) / (1 + c^2/c^2) = 2*c / 2 = c
Isaac Newton never had any data that could have given him any suspicion about such a result. Einstein didn't have any data to suggest this either, but he was brilliant.
I hope this helps,