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About ronny fisher
Expertise
general questions on probability and statistics. please do not send intro prob/stat homework questions.

Experience
have taught probability and stats for 25 years

Education/Credentials
ba in math, phd in stats

Past/Present Clients
federal government, state AG, start-up pharma companies, engineering consulting firms, academic researchers (the list goes on).

 
   

You are here:  Experts > Science > Mathematics > Probability & Statistics > Percentages & Statistics

Probability & Statistics - Percentages & Statistics


Expert: ronny fisher - 9/28/2009

Question
QUESTION: Hello:

This is not a homework question! I am just curious to know how to solve this with a somewhat simple calculation.

Is there a method that can determine the answers to my questions by using a weighted average or some probability calculation?

(A) 5% X $2000 = $100

(B) 2% X $1000 = $20

This is a total return or an average of $120/$3000 = 4%

If I want to have an average or total return of 3%, what amounts must be in the A account and what dollar amount must be in the B account?

And also what percentage must the A and B accounts be changed to so that the average or total return is 3% but keep the dollar amounts in each account, A $2000 and B $1000, the same?

I know that this question is not directly related to probability and statistics, but perhaps you may offer some helpful solution.

I thank you for your reply



ANSWER: kenneth -

your question involves simple algebra and is not really a
probability question.

having said that, one could interpret your first question
as asking "what weighted average of 2% and 5% gives 3%?".

if the weights are w and 1-w, respectively (here w is a weight
between 0 and 1) you want to solve for w in

5w + 2(1-w) = 3.

this is a simple algebraic equation whose solution is w = 1/3.

so you put 1/3 of your money at 5% and the other 2/3 at 2% and you get
an average return of 3%.

if you have $3000, put $1000 at 5% and $2000 at 2%.

your second question does not have a unique answer. for example,
you could put $2000 at 4% and $1000 at 1% to get a 3% return. you
could also put the $2000 at 3.5% and the $1000 at 2% and get a 3%
return.

the formal solution to this question is this: let x and y be the
percentage yields for the $2000 and $1000 respectively. then you
want

(2000x + 1000y)/3000 = 3,

which simplifies to 2x + y = 9.

this is one equation in two unknowns (x and y) and has more than one
solution (for which neither x nor y are negative). in fact, it has
an infinite number of solutions. just pick a value for y, say, like
y = 1% and solve for x to get x = 4%. if you take y = 2%, you get
x = 3.5%. you could also take y = 0% and get x = 4.5%; and so on.
(you can't take y to be greater than 3%, however - since the formal
solution would then involve x being negative.)

ronny


---------- FOLLOW-UP ----------

QUESTION: Hello:

I want to thank you for the reply.

This appears to be a strange example.  In 5% X $2000 = $100 and 2% X $1000 = $20, the $3000 is divided into thirds. This is a 4% total return, $120/$3000

Now, if the amounts are switched, the $1000 earns 5% and the $2000 earns 2%, the total return is 3%, $90/$3000, but the $3000 is still divided into thirds with the second example having a one percentage point difference.

I thank you for any reply that you may want to send.


Answer
kenneth -

there are lots of curious phenomena that one encounters in the realm of
mathematics.

for example: the divisors of 28 are 1, 2, 4, 7 & 14. if you sum them,
they add up to 28. such numbers (which are the sum of their divisors)
are called perfect numbers.

there are many such - including one that is smaller than 28. can you
figure out what that smaller perfect number is?

ronny

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