AboutSurajit Basu Expertise I can answer questions which are mathematical, logical, or wordplay related.
I am not good at highly creative problems, or riddles.
Experience I regularly do puzzles, and help out friends, teenagers. I read books written by Martin Gardener. I love the puzzles and Easter eggs in Douglas Hofstadter's Godel, Escher, Bach: an enternal golden braid.
Publications A few examples of my writing:
http://surajitbasu.sulekha.com/blog/post/2006/04/the-journey-down-the-number-line.htm
Education/Credentials B. Tech. ( Computer Science), IIT Kanpur, India
MBA ( Post-Graduate Diploma in Business Management), (Finance, Systems), IIM Calcutta, India
using the numbers 0 to 9 what is the lowest integer that contains each of the numbers once only and can be divided by 2 though to 16
Answer My son gave me this puzzle to do help.
using the numbers 0 to 9 what is the lowest integer that contains each of the numbers once only and can be divided by 2 though to 16
can be divided by 2 though to 16?
So, let's find the LCM of 2 to 16...
# Needs an extra factor of because
2 2
3 3
4 2 2 is already there
5 5
6 1 2 and 3 are there
7 7
8 2 4 is there
9 3 3 is there
10 1 2 and 5 are there
11 11
12 1 3 and 4 are there
13 13
14 1 2 and 7 are there
15 1 3 and 5 are there
16 2 8 is there
So the LCM is 720,720.
So, the number we need has to be divisible by 720,720.
using the numbers 0 to 9 what is the lowest integer that contains each of the numbers once only and can be divided by 720,720
the required number has to end in a 0.
The min number is 1,234,567,890 ( has to have 10 digits)
So, 720,720 needs to be multiplied by at least ... 1,713
