Space Exploration/oservation from satellites
Expert: Joel Osborne - 7/13/2007
QuestionWhat are the advatages and disadvantages of astronomical observation from a low earth orbitting obervatory(satellite)? Please Hurry!
Answer
Okay, comments recieved and I shall explain to you the difference and explain my answer.
Basically, there are many types of observations that we can possibly take to look at the position of a satelite, which we call astronomical observations.
First is called the two line elements, or TLE's for example i'll pull up the TLE's currently for the ISS:
Satellite: ISS
Catalog Number: 25544
Epoch time: 07208.63003017 = yrday.fracday
Element set: 900
Inclination: 51.6322 deg
RA of node: 254.8574 deg
Eccentricity: .0009105
Arg of perigee: 171.0255 deg
Mean anomaly: 189.1073 deg
Mean motion: 15.75945050 rev/day
Decay rate: 2.00000E-04 rev/day^2
Epoch rev: 1716
Checksum: 265
which produces the following elements:
TWO LINE MEAN ELEMENT SET
ISS
1 25544U 98067A 07208.63003017 .00020000 00000-0 20000-3 0 9006
2 25544 51.6322 254.8574 0009105 171.0255 189.1073 15.75945050 17167
The first difference is location, location, location. This is accurate up to a certain degree, were not looking to rendezvous, maybe your just trying to look at when it might take a pass above you, this is what you would have to look for to see when to look up.
If were looking to rendezvous, were going to have to look a lot harder at location this is using some other elements, which takes a bit more of math to calculate, and its based on cartesian cordinates:
M50 Cartesian M50 Keplerian
----------------------------------- --------------------------------
X = 4095696.27 A = 6714568.69 meter
Y = -928572.89 meter E = .0009435
Z = 5235593.51 I = 51.30243
XDOT = 1933.134913 Wp = 156.08589
YDOT = 7458.968440 meter/sec RA = 254.29243 deg
ZDOT = -197.739693 TA = 295.74912
MA = 295.84648
Ha = 189.247 n.mi
Hp = 179.490
M50 Cartesian J2K Cartesian
----------------------------------- --------------------------------
X = 13437323.73 X = 4080342.12
Y = -3046498.97 feet Y = -882859.25 meter
Z = 17177144.08 Z = 5255452.66
XDOT = 6342.306146 XDOT = 1850.544523
YDOT = 24471.681232 feet/sec YDOT = 7480.124089 meter/sec
ZDOT = -648.752275 ZDOT = -188.547998
TDR Cartesian TDR Cartesian
----------------------------------- --------------------------------
X = -13322385.28 X = -4060663.03
Y = -3126067.76 feet Y = -952825.45 meter
Z = 17252213.03 Z = 5258474.53
XDOT = 4826.017195 XDOT = 1470.970041
YDOT = -23799.272928 feet/sec YDOT = -7254.018389 meter/sec
ZDOT = -613.087811 ZDOT = -186.869165
As we look at what they call the X dot Y dot and Z dot we've got an actual speed in M/S if i'm looking to hook up with the ISS I can throw those into what they call Clohessy-Wiltshire (CW) Equations or Hills equations.
Punching this out we can produce an exact time to hook up with the ISS, and you just have to put in this equation to get there, and i'll direct you to a web site that would help explain this better:
http://ccar.colorado.edu/asen5050/lecture12.pdf
So you can see what the difference is, let me know if you need anymore information regarding this difference.
Joel Osborne
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Thanks for the question.
Advantages of astronomical observations would be position of time and location, or more importantly, be where it is when we say so.
Disadvantages are that it takes a lot of math, gettting gps is just that much more quick.
Thanks, sorry for the delay.
Joel Osborne